The decision making under certainty is identifying the best option or alternative and to optimize the outcome. In decision making under certainty the various outcomes are known and their values are certain. Hence the task is merely to optimize the required criterion such as to minimize the cost or to maximize the profits. Since perfect information is rarely available on all the various parameters impacting decision, hence this technique (decision making under certainty) is less often used. Moreover in normal circumstances there is cost of information hence this cost aspect also needs to be analyzed and expected value of perfect information (EVPI) needs to be calculated. E.g. If you want to make a decision of buying a soap ‘Dove’ or ‘Pears’ and the benefits of both the soaps are same, then cost of soaps are considered. Pears soap is cheaper than Dove, so the decision will be to buy Pears.
In decision making under risk, the outcomes are known as also the probabilities of occurrence are known and in such scenario, instead of optimizing the outcome we instead optimize the expected monetary value (EMV) of outcome. The highest EMV will be selected. E.g. if there is 1% probability of earning $1000 in option A while there is 90% probability of earning $ 50 in option B , the option B shall be preferred as the EMV of option B is $ 45 (90% of $ 45) rather than EMV of $ 10 in option A (1% of $ 1000).
Under uncertainty, only the outcomes are known but not their probability. Here the selection is based on maximax, maximin or equally likely methods for the positive or cautious or neutral perspective/s respectively.
Good Economy |
Poor Economy |
|
Probability |
0.3 |
0.7 |
Share Market |
80000 |
-20000 |
Bonds |
30000 |
20000 |
Real Estate |
25000 |
15000 |
Table 1
S. No |
Good Economy |
Poor Economy |
Best Result (Max) |
|
1 |
Share Market |
80000 |
-20000 |
80000 (Max 80000,-20000) |
2 |
Bonds |
30000 |
20000 |
30000 (Max 30000,20000) |
3 |
Real Estate |
25000 |
15000 |
25000 (Max 25000,15000) |
80000 (Max(80000,30000,25000)) |
Table 2
As per Table 2, the optimist would choose share market investment because the share market returns (under best conditions) are the maximum of the maximum returns in any investment group i.e. return of $80,000 [maximax] (csuFOBJBS, Decision Analysis part 1, 2014)
S. No |
Good Economy |
Poor Economy |
Best Result (Min) |
|
1 |
Share Market |
80000 |
-20000 |
-20000 (Min 80000,-20000) |
2 |
Bonds |
30000 |
20000 |
20000 (Min 30000,20000) |
3 |
Real Estate |
25000 |
15000 |
15000 (Min 25000,15000) |
20000 (Max(-20000,20000,15000)) |
Table 3
As per Table 3, mentioned figures the pessimist will choose where he gets maximum returns out of minimum returns (pessimist option) of any investment class. The investment in Bonds will ensure him returns of $20,000/- under any circumstances [maximin].
S. No |
Regret in Good Economy |
Regret in Poor Economy |
Max Regret (Max) |
|
1 |
Share Market |
Max (80000,30000,25000) – 80000 = 0 |
Max (-20000,20000,15000) – (-20000) = 40000 |
Max (0,40000) = 40000 |
2 |
Bonds |
Max (80000,30000,25000) – 30000 = 50000 |
Max (-20000,20000,15000) – 20000 = 0 |
Max (50000,0) = 50000 |
3 |
Real Estate |
Max (80000,30000,25000)- 25000 55000 |
Max (-20000,20000,15000)- 15000 5000 |
Max (55000,5000) = 55000 |
Min Regret = Min (40000,50000,55000) = 40000 |
Table 4
As per Table 4, the criterion of regret shows regret is share market has minimum of regrets. (csuFOBJBS, Decision Analysis part 2, 2014)
S. No |
Good Economy |
Poor Economy |
Expected Value |
|
Probability |
0.3 |
0.7 |
||
1 |
Share Market |
80000 |
-20000 |
0.3 * 80000 + 0.7 * -20000 = 10000 |
2 |
Bonds |
30000 |
20000 |
0.3 * 30000 + 0.7 * 20000 = 23000 |
3 |
Real Estate |
25000 |
15000 |
0.3 * 25000 + 0.7 * 15000 = 18000 |
Max(10000,23000,18000) = 23000 |
Table 5
As per Table 5, based on probability of a good economy = 0.3, the expected monetary values suggest optimum action of investing in Bonds with expected return of $23,000
S. No |
Good Economy – Payoff |
Poor Economy – Payoff |
|
Probability |
0.3 |
0.7 |
|
1 |
Share Market |
80000 |
-20000 |
2 |
Bonds |
30000 |
20000 |
3 |
Real Estate |
25000 |
15000 |
Max Payoff |
Max (80000,30000,25000) = 80000 |
Max (-20000, 20000,15000) = 20000 |
|
Expected value with perfect information |
Max Payoff * Probability = 80000 * 0.3 = 24000 |
Max Payoff * Probability = 20000 * 0.7 = 14000 |
Table 6
Expected value without perfect information (EMV) = Maximum expected monetary value i.e. (Max EMV) = $23,000
As per Table 6:
Expected value with perfect information = $24000 + 14000 = $38,000
Expected value of perfect information (EVPI) = Expected value with perfect information – Expected value without perfect information = $38,000 – $23,000 = $15,000
S. No |
Good Economy |
Poor Economy |
Expected Monetary Value |
|
Probability |
0.5 |
0.5 |
||
1 |
Large Shop (a1) |
80000 |
-40000 |
(0.5 * 80000) + (0.5 * (-40000)) = 20000 |
2 |
Small Shop (a2) |
30000 |
-10000 |
(0.5 * 30000) + (0.5 * (-10000)) = 10000 |
Max (20000,10000) = 20000 |
Table 7
Based on expected market value, Jerry should choose, large shop (a1) as the expected return is higher at $ 20,000 as compared to return of $ 10,000 in small shop (a2).
The prior probability of Good Market Signal =
Probability (says good) = Probability (says good | actual good market) * Probability (actual good market) + Probability (says good but actual bad market) * Probability (actual bad market)
= 0.8 * 0.5 + 0.4 * 0.5 = 0.6
The prior probability of Poor Market Signal = 1 – 0.6 = 0.4
Probability (says good | actual good market) * Probability (good market) = Probability (good market & says good) * Probability (says good)
0.8 * 0.5 = Probability (good market & says good) * 0.6
Hence, Probability (good market & says good) = 0.8 * 0.5 / 0.6 = 2/3
And Probability (bad market & says good) = 1 – 2/3 = 1/3
Probability(says good & bad market) Probability(bad market) = Probability( good market & says bad) Probability(says bad)
0.2 * 0.5 = Probability(good market & says bad) * 0.4
Hence , Probability(good market & says bad) = 0.2*0.5/0.4 = 0.25
And , Probability(bad market & says bad) = 1-0.25 = 0.75
Expected profit (good market & large shop):
EMV (large) = 80000 * (2/3) – 40000 * (1/3) = 40000
Expected profit (good market & small shop):
EMV (small) = 30000 * (2/3) – 10000 * (1/3) = 16666.67
Hence if the prediction is for good market then large shop should be opened.
Expected profit (bad market & large shop):
EMV (large) = 80000 * 0.25 – 40000 * 0.75 = -10000
Expected profit (bad market & small shop):
EMV (small) = 30000 * 0.25 – 10000 * 0.75 = 0
Hence if the prediction is for bad market then small shop should be opened.
The posterior probability of a good market given that his friend has provided an
unfavorable market prediction.
Probability(says good & bad market) Probability(bad market) = Probability(good market & says bad ) Probability(says bad)
0.2 * 0.5=Probability ( good market & says bad ) * 0.4
Hence, Probability(good market & says bad ) = 0.2 * 0.5 / 0.4 = 0.25
Hence, Probability( bad market & says bad ) = 1 – 0.25 = 0.75
Therefore 0.25 is the required probability
After engaging his friend the expected monetary value, i.e. EMV (info) improves to $ 24000 from $ 20000 previously. Hence he stands to gain $ 4000. However, there is cost of information i.e. $ 3000 so his net gain would be $ 1000 if he engages his friend’s services. (csuFOBJBS, Value of information v2, 2015)
Data
Selling Price: $ 60 to $ 80 (uniform distribution)
Fixed Cost $ 1500 / month
Profit Margin: 20% to 30% of selling price
Prob |
Cum Probability |
Demand |
0.05 |
0.05 |
100 |
0.10 |
0.15 |
120 |
0.20 |
0.35 |
140 |
0.30 |
0.65 |
160 |
0.25 |
0.9 |
180 |
0.10 |
1 |
200 |
Table 8
Monthly Demand: LOOKUP(RAND(), Cumm Probability, Demand)
Profit Margin: 20% (Minimum profit) + 30%-20% (Max margin – Min Margin) * Rand()
Selling price = =RANDBETWEEN (Min Selling price, Maximum Selling price)
Monthly Profit = Monthly Demand * Profit Margin * Selling price – Fixed Cost
Month |
Monthly Demand |
Profit Margin |
Selling Price |
Monthly Profit |
1 |
100 |
0.266360392 |
70 |
364.52 |
2 |
140 |
0.247115827 |
65 |
2248.45 |
3 |
100 |
0.215591232 |
65 |
1401.34 |
4 |
140 |
0.230139687 |
78 |
2513.13 |
5 |
140 |
0.233413401 |
63 |
2058.71 |
6 |
160 |
0.255822859 |
62 |
2537.76 |
7 |
140 |
0.296303417 |
65 |
2696.36 |
8 |
120 |
0.28794513 |
64 |
2211.42 |
9 |
120 |
0.244070117 |
71 |
2079.48 |
10 |
120 |
0.243390276 |
70 |
2044.48 |
11 |
120 |
0.260346493 |
73 |
2280.64 |
12 |
160 |
0.240350633 |
61 |
2345.82 |
Table 9
Month |
OH Cost |
MH |
Batches |
1 |
$80,000 |
2,200 |
300 |
2 |
40,000 |
2,400 |
120 |
3 |
63,000 |
2,100 |
250 |
4 |
45,000 |
2,700 |
160 |
5 |
44,000 |
2,300 |
200 |
6 |
48,000 |
3,800 |
170 |
7 |
65,000 |
3,600 |
260 |
8 |
46,000 |
1,800 |
160 |
9 |
33,000 |
3,200 |
150 |
10 |
66,000 |
2,800 |
210 |
Total |
530,000 |
26,900 |
1,980 |
Table 10
Lowest MH = 1800 therefore lowest OH Cost = 46000
Variable Cost (per unit) = (Highest OH Cost – Lowest OH cost)/ (Highest MH – Lowest MH)
= (48000 – 46000) / (3800 – 1800)
= 2000 / 2000 = $ 1 per unit
Total Fixed Cost = Highest OH Cost – (Highest MH * Variable Cost)
= 48000 – (3800 * 1)
= 48000 – 3800 = $44200
Cost Volume = Fixed Cost + (Variable Cost * Machine Hours)
= 44200 + (1 * 3000) = 44200 + 3000 = $47200
Regression Analysis
Overhead Cost against Machine Hours
SUMMARY OUTPUT |
|||||||||
Regression Statistics |
|||||||||
Multiple R |
0.104236344 |
||||||||
R Square |
0.010865215 |
||||||||
Adjusted R Square |
-0.112776633 |
||||||||
Standard Error |
15447.61363 |
||||||||
Observations |
10 |
||||||||
ANOVA |
|||||||||
df |
SS |
MS |
F |
Significance F |
|||||
Regression |
1 |
20969865.79 |
20969865.79 |
0.087876521 |
0.774444342 |
||||
Residual |
8 |
1909030134 |
238628766.8 |
||||||
Total |
9 |
1930000000 |
|||||||
Coefficients |
Standard Error |
t Stat |
P-value |
Lower 95% |
Upper 95% |
Lower 95.0% |
Upper 95.0% |
||
Intercept |
59198.7845 |
21473.78291 |
2.75679347 |
0.024797288 |
9680.152308 |
108717.4167 |
9680.152308 |
108717.4167 |
|
MH |
-2.304380856 |
7.773521992 |
-0.296439742 |
0.774444342 |
-20.23015471 |
15.621393 |
-20.23015471 |
15.621393 |
Y = Intercept + Slope * units
OH= 59198.7845 – 2.304380856 * MH
Since the P value (in table above) is high and R (or R square) is low, hence correlation is low and result is not statistically significant and not a good fit.
Overhead Cost against Batches
SUMMARY OUTPUT |
||||||||
Regression Statistics |
||||||||
Multiple R |
0.911766618 |
|||||||
R Square |
0.831318365 |
|||||||
Adjusted R Square |
0.810233161 |
|||||||
Standard Error |
6379.219736 |
|||||||
Observations |
10 |
|||||||
ANOVA |
||||||||
df |
SS |
MS |
F |
Significance F |
||||
Regression |
1 |
1604444444 |
1604444444 |
39.42662116 |
0.000238105 |
|||
Residual |
8 |
325555555.6 |
40694444.44 |
|||||
Total |
9 |
1930000000 |
||||||
Coefficients |
Standard Error |
t Stat |
P-value |
Lower 95% |
Upper 95% |
Lower 95.0% |
Upper 95.0% |
|
Intercept |
6555.555556 |
7666.867952 |
0.855050015 |
0.417393566 |
-11124.27365 |
24235.38476 |
-11124.27365 |
24235.38476 |
Batches |
234.5679012 |
37.35715567 |
6.279062124 |
0.000238105 |
148.4221458 |
320.7136567 |
148.4221458 |
320.7136567 |
Y = Intercept + Slope * units
OH= 6555.555556 + 234.5679012 * Batches
Since the P value (in table above) is low and R (or R square) is high, hence correlation is high and result is statistically significant and good fit.
Overhead Cost against Machine Hours and Batches
SUMMARY OUTPUT |
||||||||
Regression Statistics |
||||||||
Multiple R |
0.912733424 |
|||||||
R Square |
0.833082304 |
|||||||
Adjusted R Square |
0.785391534 |
|||||||
Standard Error |
6783.92168 |
|||||||
Observations |
10 |
|||||||
ANOVA |
||||||||
df |
SS |
MS |
F |
Significance F |
||||
Regression |
2 |
1607848846 |
803924423.2 |
17.46841786 |
0.001900021 |
|||
Residual |
7 |
322151153.5 |
46021593.36 |
|||||
Total |
9 |
1930000000 |
||||||
Coefficients |
Standard Error |
t Stat |
P-value |
Lower 95% |
Upper 95% |
Lower 95.0% |
Upper 95.0% |
|
Intercept |
9205.657918 |
12704.91845 |
0.724574341 |
0.492215314 |
-20836.70036 |
39248.0162 |
-20836.70036 |
39248.0162 |
MH |
-0.930666774 |
3.421799934 |
-0.271981645 |
0.793483511 |
-9.021937883 |
7.160604336 |
-9.021937883 |
7.160604336 |
Batches |
233.827453 |
39.8202902 |
5.872068031 |
0.000616648 |
139.6674291 |
327.987477 |
139.6674291 |
327.987477 |
OH= 9205.657918 – 0.930666774 * MH + 233.827453 * Batches
Since the P value (in table above) is low and R (or R square) is high, hence correlation is high and result is statistically significant and good fit.
Using both Machine Hours and Batches, the R square is highest and P value is lowest. Hence this model should be preferred in future.
Batches = 150
Overhead Cost = 9205.657918 – 0.930666774 * MH + 233.827453 * Batches
= 9205.657918 – (0.930666774 * 2000) + (233.827453 * 150)
= 9205.657918 – 1861.333548 + 35074.11795 = $42418.44232
Product A |
Product B |
Total |
|
Sales price per unit (A) |
$10 |
$20 |
|
Variable cost per unit (B) |
$5 |
$12 |
|
Fixed Cost |
$4,000 |
Table 11
: 10 – 5 = $5 per unit
: 20 – 12 = $8 per unit
: Fixed Cost / Unit Contribution
: 4000 / 8 = 500 units
Break Even Sales Volume = Fixed Cost / Contribution Margin Ratio
Contribution Margin Ratio = Unit Contribution Margin / Sales Price per unit
= 5 / 10 = 0.50
Hence,
Break Even Sales Volume = 4000 / 0.50 = $8000
Fixed Cost = $ 4000
Hence, Contribution = Profit before Tax + Fixed Cost
= $5000 + $4000 = $9000
Total contribution is:
(Unit Contribution Margin for Product A*2)+Unit Contribution Margin for Product B
($5 * 2) + $8 = $10 + $8 = $18
Hence the number of units of Product B required to be produced = 9000 / 18
= 500 units
Since Product A and Product B are produced in the ratio 2:1, so Product A is produced = 500 * 2 = 1000 units
30 cent in the dollar = 1 – 0.30 = 0.70
Profit before Tax = Profit after Tax / 30 cent in Dollar
= 21000 / 0.70 = 30000
Total contribution for 1 unit B and 2 units of A: $18
Total Units of Product B = (Profit + Fixed Cost) / Variable Cost
= (4000 + 30000) / 18 = 34000 / 18 = 1889 units
Since Product A and Product B are produced in the ratio 2:1:
Total Units of Product A = 1889 * 2 = 3778 units
References
csuFOBJBS. (2014, August 26). Decision Analysis part 1. Retrieved from https://www.youtube.com/watch?v=kGNJhtmaAWM&feature=youtu.be
csuFOBJBS. (2014, August 26). Decision Analysis part 2. Retrieved from https://www.youtube.com/watch?v=MNWFhxPHx-o&feature=youtu.be
csuFOBJBS. (2015, March 3). Value of information v2. Retrieved from https://www.youtube.com/watch?v=m58do9gIhOY&feature=youtu.be
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