To determine price and output of a cartel, we consider a two member firm. The cartel’s industry demand curve would be its aggregate demand curve as shown by DD in the figure given below. Below the demand curve lies the marginal revenue curve of the cartel. The marginal cost curve of the cartel (MCT) is the aggregate or horintal aggregate of the MC curves of both firms A and B (MCA and MCB). Again, the output of each firm is distributed in a way that the marginal costs are equal (Shapiro,1989). The cartel’s profit is maximized where MR is equal to MC which here is shown as point C. The profit maximizing output is here, OQ* and the price is OP*. We see in the figure that when firm A produces OQ1 and firm B produces OQ2 , the marginal costs of the firm is equal. OQ* is the sum of OQ1 and OQ2 with A’s profit PFTK and B’s PEGH, the sum of which is maximum (Hall et al, 2010).
(a) The given demand function is
P=1,000 – QS – QT
Where QS and QT are the quantities sold by the respective firms and P is the (market) selling price. The total cost functions of manufacturing and selling the component for the respective firms are:
TCs = 70,000 + 5QS+ 0.25Q²S
TCt = 110,000 + 5QT + 0.15Q²T
Total profit of S is:
ΠS = PQs-TCs= (1000-Qs-Qt)Qs – 70,000 + 5QS+ 0.25Q²S
=-70000+995QS-QsQT-1.25Qs2
Taking partial derivative of the above equation with respect to Qs gives us (Varian, 2010):
dPs/dQs= 995-Qt-2.50Qs………………………………… (1)
Similarly we get firm T’s total profit as:
Π T= PT-TCT= (1000-QS-QT) QT – 110,000 + 5QT + 0.15Q²T
=-110000+995QT-QS QT -1.15QT2
On taking partial derivatives with respect to Qt we obtain as follows:
dPt/dQT = 995-QS-2.3QT…………………………………………(2)
We see the first equation are functions of QS and QT
Setting both equation 1 and 2 to zero yields:
2.50Qs+Qt=995
Qs+2.30Qt=995
As we solve the two equations we get, QS*=272.32 units and QT*=314.21 units. On substituting these two values in the demand equation we get the equilibrium selling price of P*=$413.47 per unit and the profits obtained are:
Π S=$ 22695 and
Π T=$3536.17.
π = πs+πt
=PQS-TCS+PQT-TCT
π= (1000-Qs-Qt) Qs – 70,000 + 5QS+ 0.25Q²S + (1000-Qs-Qt) Qt – 110,000 + 5QT + 0.15QT2
= 180000+995Qs-1.25Qs2+995Qt-1.15Q2-2QsQt
To maximize this total profit we take partial derivative with respect Qs and Qt respectively:
dPR/dQs= 995-2.50Qs-2Qt
dPR/dQt=995-2.30Qt-2Qs
Setting these equal to zero we obtain:
995-2.50Qs-2Qt=0
995-2.30Qt-2Qs=0
.On solving we get Qs*=170.57units and Qt*=284.39units. Substituting these in the price functions and profit function gives P*=$545.14 per unit and PR*=$46291.43
The Marginal costs for each firm would be:
MCs= d(TCs)/dQs= 5+0.5Qs
MCt= d(TCt)/dQt= 5+0.3Qt
The marginal cost function as obtained before, on substituting values we get: MCs*=MCt*=$90.29
Reference
Pindyck, R. Rubinfeld, D. & Mehta, P. (2009). Microeconomics. South Asia: Pearson
Hall, R., & Lieberman, M., ( 2010). Economics: Principles and applications, USA: CengagE learning
Shapiro, C. (1989). Theories of Oligopoly behavior. Available at: https://www.sciencedirect.com/science/article/pii/S1573448X89010095 [Accessed 9 March 2017]
Varian, H. (2010). Intermediate microeconomics. New Delhi:Affiliated East-West Press
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