1) Aims and Hypothesis
The researcher wants to know about the effect of O2 max test technique on the sedentary teenagers before and after a training. To find the evidence about the effect of O2 max test technique, he completed the training program twice over the sedentary teenagers, first while consuming a 200 mL beetroot juice supplement and other one with a placebo.
The objective of the study is to find the difference in change in O2 max and association between the changes in O2 max performance for the two training programs.The hypothesis to find the evidence of performance difference between the two training programs is defined as below:
Null Hypothesis: The difference exists between the mean percentage changes in O2 max after each program. Mathematically it is defined as:Alternate hypothesis: There is a difference between the mean percentage changes in O2 max after each program. Mathematically it is defined as:
Here, is the mean percentage changes in O2 max after providing beetroot supplement and is the mean percentage changes in O2 max after providing placebo supplement. The hypothesis to find the evidence of a relationship exists in O2 max performance between the two training programs is defined as below:
Null Hypothesis: The population correlation coefficient between the change O2 max in performance of two training is equal to 0:Alternate hypothesis: The population correlation coefficient between the change O2 max in performance of two training is not equal to 0:
2) Methods
The data can be divided into two categories as qualitative or quantitative. The qualitative data contains the qualitative values in different levels as binary, nominal and ordinal and the quantitative data contains the numeric values (Tesch, 2013). Thus, in this case the data for O2 max test technique on the sedentary teenagers before and after a training is quantitative.
The statistical tests applies on the basis of research design, type of variable and the distribution of data. If the data is distributed normally, then the parametric tests used for analysis, and if the data is not normally distributed then the non-parametric tests use for the analysis.
The t-test applied to test whether the mean of a sample is a characteristic of the population or not. The t-test applied on the samples which contains quantitative values and variables measured in the interval or ratio level. The sample size of t-test should be less than 30 and the population standard deviation is unknown. (Davis, 2013). Thus, the one sample is tested twice with two training programs, so the samples are related to each other. Hence, to test that there is a difference in O2 max performance between the training programs, the dependent sample t-test will be used.
In this problem Percentage change in VO2 max pre and post, so two samples of Training with Beetroot supplement and Training without Beetroot supplement (Placebo) are dependent and two paired-samples t-test will be used to understand whether there was a difference in O2 max performance between the two samples.
Assumptions of the paired-samples t-test:
To check the assumptions of normality and outliers, follow the below process:
iii. Now, click on the “Plots” option and select the “Normality plots with tests”.Click on the “Continue” option and then press “OK” to get the results.
The obtained results are shown below: The obtained boxplots are shown below:
The t-test procedure:To test that difference in O2 max performance exists, use SPSS software, the procedure is as follows:
iii. Press “OK” option in the above dialog box to get output. The screenshot of the obtained output is shown below: Test of relationship:Scatterplot: The scatterplot indicates the visual relationship between two variables. One variable can be consider as independent and other as dependent. If value of one variable increases and the corresponding value of another variable also increases then it indicates positive association between the variables.
If value of one variable increases and the corresponding value of another variable also decreases then it indicates negative association between the variables. (Cohen, Cohen, West, & Aiken, 2013). To make the scatterplot, follow the below procedure in SPSS software:
Correlation: It is a degree of relationship between the two numeric variables which contain a numeric value between -1 to +1. (Jolley & Mitchell, 2012) The negative value of correlation coefficient (r) indicates a negative association between the variables and the positive value of correlation coefficient (r) indicates a positive association between the variables.
The Pearson correlation used to know whether correlation coefficient is 0 or not.
Thus, the one sample is tested twice with two training programs, so to know about the relationship between the changes O2 max in performance between the two training programs the Pearson product-moment correlation will be used.
Consider the level of significance for the test as (α = 0.05).
Assumptions:
The SPSS procedure is given as below:
iii. Press “OK” option in the above dialog box.
The screenshot of the obtained output is shown below:
3) ResultsAssumptions of t-test:The variables, Training with Beetroot supplement and Training without Beetroot supplement are measured in continuous scale. So, this assumption 1 is met for t-test.The two variables, Training with Beetroot supplement and Training without Beetroot supplement indicates the same subjects and includes in the both samples. So, this assumption 2 is met for t-test.The Shapiro-Wilk test provide more appropriate results for the sample size less than 50, thus in this case the data is less than 50 which indicates Shapiro-Wilk will be appropriate to test the normality.
The p-value for the Shapiro-Wilk test for both samples is greater than 0.05 level of significance, which indicates that data is normal.The obtained boxplot for the data of two samples does not indicates strong outliers, so there are no strong outliers in the dataset.The obtained boxplots are shown below: Hence, all the conditions for the matched pair t-test are satisfied.The calculated value of test statistic is 0.373 and the degree of freedom is 14. The obtained P-value corresponding to the test statistic value is 0.715. So, the P-value is larger than the level of significance 0.05, which indicates that the null hypothesis does not gets rejected. Thus it can be concluded that there is no significance difference in change in O2 max performance between the two training programs.
Assumptions for Pearson correlation: The variables, Training with Beetroot supplement and Training without Beetroot supplement are measured in continuous scale. So, this assumption 1 is met.The scatterplot indicates a positive relationship indicates a positive linear relationship between the training with beetroot supplement and training without beetroot supplement. As the training without beetroot supplement increases the training with beetroot supplement also increases. So the assumption of linear relationship is met.The Shapiro-Wilk test provide more appropriate results for the sample size less than 50, thus in this case the data is less than 50 which indicates Shapiro-Wilk will be appropriate to test the normality.
The p-value for the Shapiro-Wilk test for both samples is greater than 0.05 level of significance, which indicates that data is normal.The obtained boxplot for the data of two samples does not indicates strong outliers, so there are no strong outliers in the dataset.Hence, all the conditions for the Pearson correlation are satisfied.The Scatterplot for the correlation between the training with Beetroot supplement and training without Beetroot supplement is shown below: The above scatterplot indicates a positive relationship indicates a positive linear relationship between the training with beetroot supplement and training without beetroot supplement. As the training without beetroot supplement increases the training with beetroot supplement also increases.
Correlation result, the value of correlation coefficient (0.905) indicates that two variables are very strongly related.Pearson correlation coefficient result, the P-value of Pearson correlation coefficient is 0.000. So, the P-value is smaller than the level of significance 0.05. Thus it can be conclude that the population correlation coefficient is not 0.
4) Conclusion
The null hypothesis of no significance difference in change in O2 max performance between the two training programs does not gets rejected, thus it can be conclude that there is no difference between the Percentage change in VO2 max test technique before and after a training intervention study.The value of correlation coefficient (0.905) indicates that two variables are very strongly related.As effect of training with Beetroot supplement increases the effect of training without Beetroot supplement (Placebo) also increases.The population correlation coefficient is not 0, so there is a relationship exists between the training with Beetroot supplement increases and training without Beetroot supplement (Placebo).
5) References
Cohen, J., Cohen, P., West, S., & Aiken, L. (2013). Applied Multiple Regression/Correlation Analysis for the Behavioral Sciences. Routledge.Davis, C. (2013). SPSS for Applied Sciences: Basic Statistical Testing. Csiro Publishing.Jolley, J., & Mitchell, M. (2012). Research Design Explained. Cengage Learning.Tesch, R., (2013). Qualitative Research: Analysis Types and Software. Routledge: Education. ,
Case Processing Summary |
|||||||||
Cases |
|||||||||
Valid |
Missing |
Total |
|||||||
N |
Percent |
N |
Percent |
N |
Percent |
||||
Training_with_Beetroot_supplement |
15 |
93.8% |
1 |
6.2% |
16 |
100.0% |
|||
Training_without_Beetroot_supplement |
15 |
93.8% |
1 |
6.2% |
16 |
100.0% |
|||
Tests of Normality |
|||||||||
Kolmogorov-Smirnova |
Shapiro-Wilk |
||||||||
Statistic |
df |
Sig. |
Statistic |
df |
Sig. |
||||
Training_with_Beetroot_supplement |
.142 |
15 |
.200* |
.942 |
15 |
.411 |
|||
Training_without_Beetroot_supplement |
.142 |
15 |
.200* |
.923 |
15 |
.213 |
|||
*. This is a lower bound of the true significance. |
|||||||||
a. Lilliefors Significance Correction |
|||||||||
Paired Samples Statistics |
|||||||||
Mean |
N |
Std. Deviation |
Std. Error Mean |
||||||
Pair 1 |
Training_with_Beetroot_supplement |
9.33 |
15 |
4.821 |
1.245 |
||||
Training_without_Beetroot_supplement |
9.13 |
15 |
4.688 |
1.211 |
|||||
Paired Samples Correlations |
|||||||||
N |
Correlation |
Sig. |
|||||||
Pair 1 |
Training_with_Beetroot_supplement & Training_without_Beetroot_supplement |
15 |
.905 |
.000 |
|||||
Paired Samples Test |
|||||||||
Paired Differences |
t |
df |
Sig. (2-tailed) |
||||||
Mean |
Std. Deviation |
Std. Error Mean |
95% Confidence Interval of the Difference |
||||||
Lower |
Upper |
||||||||
Pair 1 |
Training_with_Beetroot_supplement – Training_without_Beetroot_supplement |
.200 |
2.077 |
.536 |
-.950 |
1.350 |
.373 |
14 |
.715 |
Correlations |
|||||||||
Training_with_Beetroot_supplement |
Training_without_Beetroot_supplement |
||||||||
Training_with_Beetroot_supplement |
Pearson Correlation |
1 |
.905** |
||||||
Sig. (2-tailed) |
.000 |
||||||||
N |
15 |
15 |
|||||||
Training_without_Beetroot_supplement |
Pearson Correlation |
.905** |
1 |
||||||
Sig. (2-tailed) |
.000 |
||||||||
N |
15 |
15 |
|||||||
**. Correlation is significant at the 0.01 level (2-tailed). |
|||||||||
Case Processing Summary |
|||||||||
Cases |
|||||||||
Valid |
Missing |
Total |
|||||||
N |
Percent |
N |
Percent |
N |
Percent |
||||
Training_with_Beetroot_supplement |
15 |
93.8% |
1 |
6.2% |
16 |
100.0% |
|||
Training_without_Beetroot_supplement |
15 |
93.8% |
1 |
6.2% |
16 |
100.0% |
|||
Tests of Normality |
|||||||||
Kolmogorov-Smirnova |
Shapiro-Wilk |
||||||||
Statistic |
df |
Sig. |
Statistic |
df |
Sig. |
||||
Training_with_Beetroot_supplement |
.142 |
15 |
.200* |
.942 |
15 |
.411 |
|||
Training_without_Beetroot_supplement |
.142 |
15 |
.200* |
.923 |
15 |
.213 |
|||
*. This is a lower bound of the true significance. |
|||||||||
a. Lilliefors Significance Correction |
|||||||||
Paired Samples Statistics |
|||||||||
Mean |
N |
Std. Deviation |
Std. Error Mean |
||||||
Pair 1 |
Training_with_Beetroot_supplement |
9.33 |
15 |
4.821 |
1.245 |
||||
Training_without_Beetroot_supplement |
9.13 |
15 |
4.688 |
1.211 |
|||||
Paired Samples Correlations |
|||||||||
N |
Correlation |
Sig. |
|||||||
Pair 1 |
Training_with_Beetroot_supplement & Training_without_Beetroot_supplement |
15 |
.905 |
.000 |
|||||
Paired Samples Test |
|||||||||
Paired Differences |
t |
df |
Sig. (2-tailed) |
||||||
Mean |
Std. Deviation |
Std. Error Mean |
95% Confidence Interval of the Difference |
||||||
Lower |
Upper |
||||||||
Pair 1 |
Training_with_Beetroot_supplement – Training_without_Beetroot_supplement |
.200 |
2.077 |
.536 |
-.950 |
1.350 |
.373 |
14 |
.715 |
Correlations |
|||||||||
Training_with_Beetroot_supplement |
Training_without_Beetroot_supplement |
||||||||
Training_with_Beetroot_supplement |
Pearson Correlation |
1 |
.905** |
||||||
Sig. (2-tailed) |
.000 |
||||||||
N |
15 |
15 |
|||||||
Training_without_Beetroot_supplement |
Pearson Correlation |
.905** |
1 |
||||||
Sig. (2-tailed) |
.000 |
||||||||
N |
15 |
15 |
|||||||
**. Correlation is significant at the 0.01 level (2-tailed). |
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