Function
The purpose of this experiment is to form tetraamminecopper( II) sulphate hydrate and figure out the yield.
Products
CuSo4ï ¿ 1/2 5H2O.
NH3 (concentrated).
Ethanol.
50 cm3 measuring cylinder.
250 cm3 beaker.
Spatula.
Devices for vacuum purification.
Procedure.
Weigh out roughly 5.0 g of CuSo4ï ¿ 1/2 5H2O.
Dissolve it in 30 cm3 water in the beaker.
Add 10 cm3 concentrated ammonia (NH3) and stir the option.
Include 40 cm3 ethanol and stir carefully for a couple of minutes.
Filter the solution through devices for vacuum purification.
Transfer the item to a clean weighing boat and leave to dry.
Procedure and observations in class.
First 5.01 g of CuSo4ï ¿ 1/2 5H2O was weighed out. After it was liquified in 30 cm3 water, in the beaker, the solution got the colour blue. Next was 10 cm3 concentrated ammonia (NH3), which was included into the option and the colour dark blue was observed. Then 40 cm3 ethanol was included and the service got the colour intense blue. Then the service was filtered through a Buchner flask and the final item was weighed in a plastic weighing boat.
The total mass was 5.98 g, from which the weight of the boat, 1.16 g, needs to be deducted. So the mass of the end product was 5.98 – 1.16 = 4.82 g.
Data processing.
1. “Compute the variety of moles CuSo4ï ¿ 1/2 5H2O utilized.”.
To find out the variety of moles the formula n = m/ Mr needs to be utilized.
Mr = 64 + 32 + (16 x 4) + (5 x 16) = 250.
m = 5.01.
n = 5.01/ 250 = 0.02004 ï ¿ 1/2 0.0200 moles (3 s.f.).
2. “Focused ammonia consists of 25% NH3 by mass. The density of focused ammonia is 0.91 g/cm3. Calculate the number of moles of NH3.”.
Density of con. ammonia = 0.91 g/cm3 and in the procedure there was utilized 10 cm3, so for that reason mass of ammonia utilized: 0.91 x 10 = 9.1 g.
Considering that just 25% of ammonia is NH3, mass of NH3: 9.1 x 0.25 = 2.275 g.
From here the amount of moles can be calculated by the formula n = m/ Mr.
Mr = 14 + (1 x 3) = 17
m = 2.275g
n = 2.275 / 17 = 0.134 moles (3 s.f.)
3. “Which of the reactants is in excess? Which is the limiting reagent?”
CuSo4�5H2O
NH3
Number of moles (n)
0.02
0.134
Divide by smallest ratio
0.02 / 0.02 = 1
0.134 / 0.02 = 6.7
Divide by stoichiometric co-efficient from equation
(Equation below this table)
1 / 1 = 1
6.7 / 4 = 1.675
Reactant in excess or limiting reagent
Limiting reagent
Reactant in excess
(1)CuSO4 . 5H2O + 4NH3 –> Cu(NH3)4SO4 . H2O + 4H2O
4. “Calculate the theoretical yield of Cu(NH3)4SO4 . H2O”
From the equation above it can be seen that the ratio between CuSO4 . 5H2O and Cu(NH3)4SO4 . H2O is 1 : 1. Therefore 0.02 moles of CuSO4 . 5H2O will give 0.02 moles of Cu(NH3)4SO4 . H2O. By using the formula m = Mr x n the theoretical yield can be calculated:
n = 0.02
Mr = 246
m = 0.02 x 246 = 4.92 g
“Calculate the yield in percentage of the theoretical and comment on any difference.”
The yield in percentage can be calculated by the “formula”: actual mass / expected mass. 4.82 / 4.92 � 97.9% (3 s.f)
Because the difference is so small (2.1%) the experiment can be considered successful. The difference could have been caused by different things like: a small measurement mistake, a little bit was spilt or not transferred when the solution was held in the Buchner flask.
Remember! This is just a sample.
You can get a custom paper by one of our expert writers.
Get your custom essay
Helping students since 2015
Essay Writing Service Features
Our Experience
No matter how complex your assignment is, we can find the right professional for your specific task. Contact Essay is an essay writing company that hires only the smartest minds to help you with your projects. Our expertise allows us to provide students with high-quality academic writing, editing & proofreading services.
Free Features
Free revision policy
$10Free bibliography & reference
$8Free title page
$8Free formatting
$8How Our Essay Writing Service Works
First, you will need to complete an order form. It's not difficult but, in case there is anything you find not to be clear, you may always call us so that we can guide you through it. On the order form, you will need to include some basic information concerning your order: subject, topic, number of pages, etc. We also encourage our clients to upload any relevant information or sources that will help.
Complete the order form
Once we have all the information and instructions that we need, we select the most suitable writer for your assignment. While everything seems to be clear, the writer, who has complete knowledge of the subject, may need clarification from you. It is at that point that you would receive a call or email from us.
Writer’s assignment
As soon as the writer has finished, it will be delivered both to the website and to your email address so that you will not miss it. If your deadline is close at hand, we will place a call to you to make sure that you receive the paper on time.
Completing the order and download
