Q1. With diagrams describe the ways that the human body gains or loses heat to its environment. Explain how these mechanisms work. (20 marks)
Prior of highlighting the environmental impact on the body of human Considerations should be taken by individuals about the heat producing capacity of human body in the absence of influential factors like temperature or environment. The food that is been intake by human beings are been transferred to metabolism that is known as energy. For the whole digestion process the body of human releases heat. Research done by scientists has indicated that 80% of energy gained by eating food has been released as heat and the remaining 20 % of heat is been consider as providing benefit to human bodies.
The metabolic processes taking place within the human bodies can be classified into two processes:
The human body might gain and lose heat. The gain or lose of the heat depends on environment. The understated processes describes how bodies are been affected by environment.
High temperatures are been replaced by cool air in our bodies. The replacement is been initiated with trigger movement of winds or mechanical fans. This increases the process of convection within the human bodies. When temperatures are high the cooling by process of convection does not exists within the bodies and there is as increase in temperature for excessive heat.
The perfect examples are exposure to fire or sun that increases the level of temperatures within the human bodies. On the other hand snow and cold winds helps in cooling the bodies by the process of heat losing.
Research shows the amount of heat that can be expelled by the above processes:
Radiation- 45%
Convection- 30%
Evaportation-25%
Q2. For an uninsulated brick veneer house in Sydney in winter describe the main paths of heat loss to the outside air. (Hint: Use a diagram showing a section through the building) (20 marks)
The major purpose that a building has is allowing the cool temperatures during the time of summer and having warm temperatures at the time of winters for the people living there. In the time of winter high heat loss is been faced by brick veneer home from the external walls in the location of Sydney.
The paths of heat loss are been mentioned below:
Ceiling (25 to 35%)- It is found out that the roofs or the ceilings contributed about 25 to 35% for discharging the heat outside. It is also been identified that the portion of ceiling is the susceptible section in the house for discharging the heat. Ceiling is the most vulnerable section as the heat losses has a tendency to rise upward which begins the process of convection in winter. Convection helps the group of molecules to move within the hot fluid that causes the sinking of denser material within the house and relatively less dense material raise in cold environment due to gravity.
Brief Comparison- During the summer season the dwellings roof has the capacity of drawing extra amount of heat ranging from 25 to 35 percent as been compared to other seasons. When it is been compared on the ground of other houses ceiling is exposed mostly to sun that results for the generation of great amount of solar heat. For stabilising the gaining and losing of heat insulation is been applied in between the joists of ceiling.
Walls (15 % to 25 %) – 15 to 25 percent of hot air is been discharged from the veneer home walls. Therefore, it is been suggested to all the residents that insulation of home should be done appropriately. The home safeguard could be done by insulating it from the outside freezing weather. Inappropriate insulation of walls led to experiencing of a cold weather as the outside bricks become too cold and all the heat from the home goes outside due to bad insulation.
Brief Comparison: A rating of 15-25% is apparently applicable amid the period of summer where the blocks utilized for the structure draw the warmth. Insulation is incorporated inside the structural wall, 15 to 25 percent heat decrease flowing of heat will occur because of the ingestion utilizing this material.
Air Leakage (15 to 25 percent)- It is been found air spillages release almost 15-25% of warmth to the outside. All through the winter, the icy air goes through the block work and at last discovers the way by windows/entryways and any kind of gaps or potentially crevices inside home that gives a pathway to heat to get away from the house. Rooms that don’t have any immediate daylight will likewise “drain” sun based warming from the structure. They should work out of lightweight materials and can be warmed inconsistently. The surrender impact will happen when tall walls inside shaded zone assimilate up warmth and at last release out of building.
Brief Comparison- Summer is been famous for extraordinary temperatures that influence building foundation. The walls arranged inside homes assimilate the gain of heat rating of around 5-25% as opposed to the winter period of roughly 15-25% loss of heat. Inside the burning summer seasons our homes become defenceless to solid sunlight that enters homes as well as are ingest inside walls. This ingestion builds the temperature while lessening air spillage inside our homes.
Windows (10 to 20 percent) – It is been found that windows inside a home releases about 15-25% of warmth to outside air. Gaining or lossing of heat is crucial all through windows as a result of low thermal resistance that the sun enters. Convection permits loss of heat through window. Warmed air still can come inside cooled glass from window’s top end, regardless of the possibility that a curtain to be introduced. Once air gets cooled it winds up plainly thicker as well as increases. Cooled air is then substituted with more sultry air near the rooftop/roof and convection becomes evident.
Brief Comparison: A rating of 10-20% is apparently applicable amid the period of summer. A gyprock shaped or pre-assembled pelmet is utilized to anticipate warmed air achieving the window’s top end. Windows that are been shadowed with the help of pelmets is not only successful in winter additionally very viable at the time of summer. Despite the fact that warmth can in any case get to the home, air will constrained to its travel way and wont ready to go behind the window ornament and all through whatever remains of the room. Another method for reflecting warmth far from a window utilization of light-hued backings those are profoundly valuable. All curtains around windows should be closed to limit heat leaving the home during nights of cold winter season as well as to limit entering in the hot summer days.
Floor (10 to 20 percent)- The floor inside the house is recognized to discharge around 10-20 percent of warmth to outside air. Un-protected floors are helpless to losing heat in winter, unequivocally when warm capacity is required.
Brief Comparison: A rating of 10-20% is apparently applicable in the period of summer where the floor utilized the heat to attract. Insulation should be applied in the floor structure. The warmth inflow increases inside the floor, shielding the floor from getting cold. Many deck frameworks incorporate conduction that aids safeguard the heat of the floor.
Q3. Do a quick calculation of the thermal conductance (U value) across a cavity wall consisting of:
The necessary data can found in module 5. Compare this with the worked example of an insulated brick veneer wall in the worked example. Show your working.
Discuss whether or not cavity brickwork is a thermally efficient wall for housing in Australia. (20 marks)
U = 1/Rt
Brickwork
Thermal Conductivity = 1.22 W/m.oC(given in notes)
Resistivity – Kb = 1/1.22
= 0.09 m2.oC/W
According to Table 2: external conductance fo = 81.20 W/m2.oC;
internal conductance fi = 8.12 W/m2.oC
Ro = 1/fo
= 1/81.20
= 0.0123m2.oC/W
Internal Resistance
Ri = 1/fi
= 1/8.12
= 0.123m2.oC/W
Cavity Resistance
30mm Cavity (not provided on table 3)
30mm = 0.152m2.oC/W (Based on interpolate)
example of Worked interpolate;
20mm = 0.151
30mm = x
40mm = 0.153
0.153 – 0.151 = 0.002
0.153 – x
= 0.153 – x / 0.002
= 10/20
x = 0.153 – (0.002 x ½)
x = 0.153 – 0.001
x = 0.152.
10mm Plasterboard having Thermal Resistance of = 0.06 m2.oC/W
(Thermal Resistance provided within the notes)
Rp = 0.06 m2.oC/W
Insulation Resistance obtained from Diagram of Worked Example.
Rinsul = 2.5 m2.oC/W
Rt = 0.09 + 0.0123 + 0.123 + 0.152 + 0.06 + 2.5
=2.9373m2.oC/W
Therefore:
U = 1/Rtotal
U = 1/ 2.9373
U = 0.34m2.oC/W
Q4. Describe some strategies for passive solar cooling in hot dry climates. (Hint: Use diagrams) (20 marks)
Q5. Describe how a solar pergola can be designed to manage the entry of direct sunlight into a building in a location like Sydney. (20 marks)
It is noticed that the establishment of pergolas has been the best approach to manage courses of sunray coming into the home. The safe house/shading provided by the pergola help with enhancing interior temperature of building. Introducing a pergola on north side of the home in summer limits the daylight entry through the windows as well as walls. For the most part the tallness of pergolas are expanded amid the winter to give access to the daylight from underneath the pergola since in winter, sun is position much lower in the sky.
Introducing extra pergola frill, for example, angle blades helps in diminishing the height of summer daylight while as yet giving the low winter daylight to enter the sharp edges as well as on the building. Prior to introducing any blade angles they should have specially craft to guarantee the width and thicknesses are made accurately to give the proper shading impact. The angle blades should cover roughly 25% for working accurately.
There is an assortment of pergolas frameworks that can be utilized to help with giving climate assurance and splendid shading, one of them is sunlight based fueled pergolas. Despite the fact that, it must be noticed that in spite the sun oriented controlled pergolas are successful in decreasing daylight and vitality inside the home, the pergolas are not translucent and in this way shut out the daylight from entering inside the pergola even in winter season. This is unproductive in permitting daylight within the house.
References
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